Another one of them puzzle things
Moderator: TheMachine
- Vetiria
- Way too much time!

- Posts: 1226
- Joined: July 3, 2002, 4:50 pm
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- Location: Decatur, IL
Another one of them puzzle things
I don't know why, but I like doing these. Everyone else seemed to enjoy them as well last time, before some person decided to derail the thread, again. So here ya go. Got this one in my e-mail today.
DON'T CHEAT BY SCROLLING DOWN FIRST
It takes less than a minute.......
Work this out as you read.
Don't cheat and read the bottom until you've worked through it!
This is fun!
1. First of all, pick the number of times a week that you would
like to have dinner out. (try for more than once but less than 10)
2. Multiply this number by 2 (Just to be bold)
3. Add 5. (for Sunday)
4. Multiply it by 50 - I'll wait while you get the
calculator............
5. If you have already had your birthday this year add 1753....
If you haven't, add 1752..........
6.. Now subtract the four digit year that you were born.
You should have a three digit number ..
The first digit of this was your original number
(I.e., how many times you want to have eat out each week.)
The next two numbers are...
YOUR AGE! (Oh YES, it IS!!!!!)
THIS IS THE ONLY YEAR (2003) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS. IMPRESSIVE, ISN'T IT?
DON'T CHEAT BY SCROLLING DOWN FIRST
It takes less than a minute.......
Work this out as you read.
Don't cheat and read the bottom until you've worked through it!
This is fun!
1. First of all, pick the number of times a week that you would
like to have dinner out. (try for more than once but less than 10)
2. Multiply this number by 2 (Just to be bold)
3. Add 5. (for Sunday)
4. Multiply it by 50 - I'll wait while you get the
calculator............
5. If you have already had your birthday this year add 1753....
If you haven't, add 1752..........
6.. Now subtract the four digit year that you were born.
You should have a three digit number ..
The first digit of this was your original number
(I.e., how many times you want to have eat out each week.)
The next two numbers are...
YOUR AGE! (Oh YES, it IS!!!!!)
THIS IS THE ONLY YEAR (2003) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS. IMPRESSIVE, ISN'T IT?
-
Fairweather Pure
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- Gurugurumaki
- Way too much time!

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- Bubba Grizz
- Super Poster!

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No, no.
It's HOW DO IT KNOW!?!?!?
http://www.quantumhealing.com/quantumhe ... t_know.htm
http://ourworld.compuserve.com/homepage ... w_know.htm
http://home.att.net/~lilo-boot/lilohome.htm
http://www.advisortoday.com/archives/20 ... ry_mm.html
http://www.larkspurschools.org/lsd/sup/2002/0916.htm
and so on...
It's HOW DO IT KNOW!?!?!?
http://www.quantumhealing.com/quantumhe ... t_know.htm
http://ourworld.compuserve.com/homepage ... w_know.htm
http://home.att.net/~lilo-boot/lilohome.htm
http://www.advisortoday.com/archives/20 ... ry_mm.html
http://www.larkspurschools.org/lsd/sup/2002/0916.htm
and so on...

RIP Goatse.cx January 14, 2004
Member of the Evil Boxing Triad
PRESIDENT OF JACKASSERY!
I last had a birthday last year, so
x the number you pick to eat out, is an integer from 1 to 9
y is the year you are born
so the equation as stated is
(2x+5)*50 +1752 - y
expand it out
100 x + 250 + 1752 - y
simplify
100 x + 2002 - y
2002 (the last year you had a birthday) - y (your birthdate) will equal your age.
Notice that if you are one hundred years or older, this doesn't work.
the other part of the equation is 100x, so unsuprisingly the first number of the three digit final result is the number you choose initially.
x the number you pick to eat out, is an integer from 1 to 9
y is the year you are born
so the equation as stated is
(2x+5)*50 +1752 - y
expand it out
100 x + 250 + 1752 - y
simplify
100 x + 2002 - y
2002 (the last year you had a birthday) - y (your birthdate) will equal your age.
Notice that if you are one hundred years or older, this doesn't work.
the other part of the equation is 100x, so unsuprisingly the first number of the three digit final result is the number you choose initially.
